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0.8x^{2}+0.2x=1.569
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
0.8x^{2}+0.2x-1.569=1.569-1.569
Subtract 1.569 from both sides of the equation.
0.8x^{2}+0.2x-1.569=0
Subtracting 1.569 from itself leaves 0.
x=\frac{-0.2±\sqrt{0.2^{2}-4\times 0.8\left(-1.569\right)}}{2\times 0.8}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 0.8 for a, 0.2 for b, and -1.569 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-0.2±\sqrt{0.04-4\times 0.8\left(-1.569\right)}}{2\times 0.8}
Square 0.2 by squaring both the numerator and the denominator of the fraction.
x=\frac{-0.2±\sqrt{0.04-3.2\left(-1.569\right)}}{2\times 0.8}
Multiply -4 times 0.8.
x=\frac{-0.2±\sqrt{0.04+5.0208}}{2\times 0.8}
Multiply -3.2 times -1.569 by multiplying numerator times numerator and denominator times denominator. Then reduce the fraction to lowest terms if possible.
x=\frac{-0.2±\sqrt{5.0608}}{2\times 0.8}
Add 0.04 to 5.0208 by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
x=\frac{-0.2±\frac{\sqrt{3163}}{25}}{2\times 0.8}
Take the square root of 5.0608.
x=\frac{-0.2±\frac{\sqrt{3163}}{25}}{1.6}
Multiply 2 times 0.8.
x=\frac{\frac{\sqrt{3163}}{25}-\frac{1}{5}}{1.6}
Now solve the equation x=\frac{-0.2±\frac{\sqrt{3163}}{25}}{1.6} when ± is plus. Add -0.2 to \frac{\sqrt{3163}}{25}.
x=\frac{\sqrt{3163}}{40}-\frac{1}{8}
Divide -\frac{1}{5}+\frac{\sqrt{3163}}{25} by 1.6 by multiplying -\frac{1}{5}+\frac{\sqrt{3163}}{25} by the reciprocal of 1.6.
x=\frac{-\frac{\sqrt{3163}}{25}-\frac{1}{5}}{1.6}
Now solve the equation x=\frac{-0.2±\frac{\sqrt{3163}}{25}}{1.6} when ± is minus. Subtract \frac{\sqrt{3163}}{25} from -0.2.
x=-\frac{\sqrt{3163}}{40}-\frac{1}{8}
Divide -\frac{1}{5}-\frac{\sqrt{3163}}{25} by 1.6 by multiplying -\frac{1}{5}-\frac{\sqrt{3163}}{25} by the reciprocal of 1.6.
x=\frac{\sqrt{3163}}{40}-\frac{1}{8} x=-\frac{\sqrt{3163}}{40}-\frac{1}{8}
The equation is now solved.
0.8x^{2}+0.2x=1.569
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{0.8x^{2}+0.2x}{0.8}=\frac{1.569}{0.8}
Divide both sides of the equation by 0.8, which is the same as multiplying both sides by the reciprocal of the fraction.
x^{2}+\frac{0.2}{0.8}x=\frac{1.569}{0.8}
Dividing by 0.8 undoes the multiplication by 0.8.
x^{2}+0.25x=\frac{1.569}{0.8}
Divide 0.2 by 0.8 by multiplying 0.2 by the reciprocal of 0.8.
x^{2}+0.25x=1.96125
Divide 1.569 by 0.8 by multiplying 1.569 by the reciprocal of 0.8.
x^{2}+0.25x+0.125^{2}=1.96125+0.125^{2}
Divide 0.25, the coefficient of the x term, by 2 to get 0.125. Then add the square of 0.125 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+0.25x+0.015625=1.96125+0.015625
Square 0.125 by squaring both the numerator and the denominator of the fraction.
x^{2}+0.25x+0.015625=1.976875
Add 1.96125 to 0.015625 by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x+0.125\right)^{2}=1.976875
Factor x^{2}+0.25x+0.015625. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+0.125\right)^{2}}=\sqrt{1.976875}
Take the square root of both sides of the equation.
x+0.125=\frac{\sqrt{3163}}{40} x+0.125=-\frac{\sqrt{3163}}{40}
Simplify.
x=\frac{\sqrt{3163}}{40}-\frac{1}{8} x=-\frac{\sqrt{3163}}{40}-\frac{1}{8}
Subtract 0.125 from both sides of the equation.