Solve 0.8*x+0.2*y=3

$$0.8 \times x+0.2 \times y=3$$

Solve for x

$$x=\frac{15-y}{4}$$

Steps for Solving Linear Equation

Subtract 0.2y from both sides.

$$0.8x=3-0.2y$$

The equation is in standard form.

$$0.8x=-\frac{y}{5}+3$$

Divide both sides of the equation by 0.8, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{0.8x}{0.8}=\frac{-\frac{y}{5}+3}{0.8}$$

Dividing by 0.8 undoes the multiplication by 0.8.

$$x=\frac{-\frac{y}{5}+3}{0.8}$$

Divide 3-\frac{y}{5} by 0.8 by multiplying 3-\frac{y}{5} by the reciprocal of 0.8.

$$x=\frac{15-y}{4}$$

Solve for y

$$y=15-4x$$

Steps for Solving Linear Equation

Subtract 0.8x from both sides.

$$0.2y=3-0.8x$$

The equation is in standard form.

$$0.2y=-\frac{4x}{5}+3$$

Multiply both sides by 5.

$$\frac{0.2y}{0.2}=\frac{-\frac{4x}{5}+3}{0.2}$$

Dividing by 0.2 undoes the multiplication by 0.2.

$$y=\frac{-\frac{4x}{5}+3}{0.2}$$

Divide 3-\frac{4x}{5} by 0.2 by multiplying 3-\frac{4x}{5} by the reciprocal of 0.2.

$$y=15-4x$$