Solve 0.8=1-((1-0.6)*(1-0.12)*(1-x_{3}))

$$0.8 = 1 - ( ( 1 - 0.6 ) \times ( 1 - 0.12 ) \times ( 1 - x _ { 3 } ) )$$

Solve for x_3

$$x_{3}=\frac{19}{44}\approx 0.431818182$$

Steps for Solving Linear Equation

Subtract 0.6 from 1 to get 0.4.

$$0.8=1-0.4\left(1-0.12\right)\left(1-x_{3}\right)$$

Subtract 0.12 from 1 to get 0.88.

$$0.8=1-0.4\times 0.88\left(1-x_{3}\right)$$

Multiply 0.4 and 0.88 to get 0.352.

$$0.8=1-0.352\left(1-x_{3}\right)$$

Use the distributive property to multiply -0.352 by 1-x_{3}.

$$0.8=1-0.352+0.352x_{3}$$

Subtract 0.352 from 1 to get 0.648.

$$0.8=0.648+0.352x_{3}$$

Swap sides so that all variable terms are on the left hand side.

$$0.648+0.352x_{3}=0.8$$

Subtract 0.648 from both sides.

$$0.352x_{3}=0.8-0.648$$

Subtract 0.648 from 0.8 to get 0.152.

$$0.352x_{3}=0.152$$

Divide both sides by 0.352.

$$x_{3}=\frac{0.152}{0.352}$$

Expand \frac{0.152}{0.352} by multiplying both numerator and the denominator by 1000.

$$x_{3}=\frac{152}{352}$$

Reduce the fraction \frac{152}{352} to lowest terms by extracting and canceling out 8.

$$x_{3}=\frac{19}{44}$$