Solve 0.8+0.6xgeq4.2

$$0.8 + 0.6 x \geq 4.2$$

Solve for x

$$x\geq \frac{17}{3}$$

Solution Steps

Subtract 0.8 from both sides.

$$0.6x\geq 4.2-0.8$$

Subtract 0.8 from 4.2 to get 3.4.

$$0.6x\geq 3.4$$

Divide both sides by 0.6. Since 0.6 is positive, the inequality direction remains the same.

$$x\geq \frac{3.4}{0.6}$$

Expand \frac{3.4}{0.6} by multiplying both numerator and the denominator by 10.

$$x\geq \frac{34}{6}$$

Reduce the fraction \frac{34}{6} to lowest terms by extracting and canceling out 2.

$$x\geq \frac{17}{3}$$