Solve for x
x=-\frac{7y}{5}+70
Solve for y
y=-\frac{5x}{7}+50
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0.5x=35-0.7y
Subtract 0.7y from both sides.
0.5x=-\frac{7y}{10}+35
The equation is in standard form.
\frac{0.5x}{0.5}=\frac{-\frac{7y}{10}+35}{0.5}
Multiply both sides by 2.
x=\frac{-\frac{7y}{10}+35}{0.5}
Dividing by 0.5 undoes the multiplication by 0.5.
x=-\frac{7y}{5}+70
Divide 35-\frac{7y}{10} by 0.5 by multiplying 35-\frac{7y}{10} by the reciprocal of 0.5.
0.7y=35-0.5x
Subtract 0.5x from both sides.
0.7y=-\frac{x}{2}+35
The equation is in standard form.
\frac{0.7y}{0.7}=\frac{-\frac{x}{2}+35}{0.7}
Divide both sides of the equation by 0.7, which is the same as multiplying both sides by the reciprocal of the fraction.
y=\frac{-\frac{x}{2}+35}{0.7}
Dividing by 0.7 undoes the multiplication by 0.7.
y=-\frac{5x}{7}+50
Divide 35-\frac{x}{2} by 0.7 by multiplying 35-\frac{x}{2} by the reciprocal of 0.7.
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