Solve 0.4+x-11/8=

$$0.4 + x - 1 \frac { 1 } { 8 } =$$

Evaluate

$$x-0.725$$

Solution Steps

Multiply 1 and 8 to get 8.

$$0.4+x-\frac{8+1}{8}$$

Add 8 and 1 to get 9.

$$0.4+x-\frac{9}{8}$$

Convert decimal number 0.4 to fraction \frac{4}{10}. Reduce the fraction \frac{4}{10} to lowest terms by extracting and canceling out 2.

$$\frac{2}{5}+x-\frac{9}{8}$$

Least common multiple of 5 and 8 is 40. Convert \frac{2}{5} and \frac{9}{8} to fractions with denominator 40.

$$\frac{16}{40}+x-\frac{45}{40}$$

Since \frac{16}{40} and \frac{45}{40} have the same denominator, subtract them by subtracting their numerators.

$$\frac{16-45}{40}+x$$

Subtract 45 from 16 to get -29.

$$-\frac{29}{40}+x$$

Expand

$$x-0.725$$

Solution Steps

Multiply 1 and 8 to get 8.

$$0.4+x-\frac{8+1}{8}$$

Add 8 and 1 to get 9.

$$0.4+x-\frac{9}{8}$$

Convert decimal number 0.4 to fraction \frac{4}{10}. Reduce the fraction \frac{4}{10} to lowest terms by extracting and canceling out 2.

$$\frac{2}{5}+x-\frac{9}{8}$$

Least common multiple of 5 and 8 is 40. Convert \frac{2}{5} and \frac{9}{8} to fractions with denominator 40.

$$\frac{16}{40}+x-\frac{45}{40}$$

Since \frac{16}{40} and \frac{45}{40} have the same denominator, subtract them by subtracting their numerators.

$$\frac{16-45}{40}+x$$

Subtract 45 from 16 to get -29.

$$-\frac{29}{40}+x$$