Solve 0.3x+0.2y=4

$$0.3x+0.2y=4$$

Solve for x

$$x=\frac{40-2y}{3}$$

Steps for Solving Linear Equation

Subtract 0.2y from both sides.

$$0.3x=4-0.2y$$

The equation is in standard form.

$$0.3x=-\frac{y}{5}+4$$

Divide both sides of the equation by 0.3, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{0.3x}{0.3}=\frac{-\frac{y}{5}+4}{0.3}$$

Dividing by 0.3 undoes the multiplication by 0.3.

$$x=\frac{-\frac{y}{5}+4}{0.3}$$

Divide 4-\frac{y}{5} by 0.3 by multiplying 4-\frac{y}{5} by the reciprocal of 0.3.

$$x=\frac{40-2y}{3}$$

Solve for y

$$y=-\frac{3x}{2}+20$$

Steps for Solving Linear Equation

Subtract 0.3x from both sides.

$$0.2y=4-0.3x$$

The equation is in standard form.

$$0.2y=-\frac{3x}{10}+4$$

Multiply both sides by 5.

$$\frac{0.2y}{0.2}=\frac{-\frac{3x}{10}+4}{0.2}$$

Dividing by 0.2 undoes the multiplication by 0.2.

$$y=\frac{-\frac{3x}{10}+4}{0.2}$$

Divide 4-\frac{3x}{10} by 0.2 by multiplying 4-\frac{3x}{10} by the reciprocal of 0.2.

$$y=-\frac{3x}{2}+20$$