Solve 0.31+(3.9*10^-4)*98^2

$$0.31+(3.9 \times { 10 }^{ -4 } ) \times { 98 }^{ 2 }$$

Evaluate

$$4.05556$$

Solution Steps

Calculate 10 to the power of -4 and get \frac{1}{10000}.

$$0.31+3.9\times \frac{1}{10000}\times 98^{2}$$

Multiply 3.9 and \frac{1}{10000} to get \frac{39}{100000}.

$$0.31+\frac{39}{100000}\times 98^{2}$$

Calculate 98 to the power of 2 and get 9604.

$$0.31+\frac{39}{100000}\times 9604$$

Multiply \frac{39}{100000} and 9604 to get \frac{93639}{25000}.

$$0.31+\frac{93639}{25000}$$

Add 0.31 and \frac{93639}{25000} to get \frac{101389}{25000}.

$$\frac{101389}{25000}$$

Factor

$$\frac{53 \cdot 1913}{2 ^ {3} \cdot 5 ^ {5}} = 4\frac{1389}{25000} = 4.05556$$