Solve 0.3x+0.1y=3

$$0.3 x + 0.1 y = 3$$

Solve for x

$$x=-\frac{y}{3}+10$$

Steps for Solving Linear Equation

Subtract 0.1y from both sides.

$$0.3x=3-0.1y$$

The equation is in standard form.

$$0.3x=-\frac{y}{10}+3$$

Divide both sides of the equation by 0.3, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{0.3x}{0.3}=\frac{-\frac{y}{10}+3}{0.3}$$

Dividing by 0.3 undoes the multiplication by 0.3.

$$x=\frac{-\frac{y}{10}+3}{0.3}$$

Divide 3-\frac{y}{10} by 0.3 by multiplying 3-\frac{y}{10} by the reciprocal of 0.3.

$$x=-\frac{y}{3}+10$$

Solve for y

$$y=30-3x$$

Steps for Solving Linear Equation

Subtract 0.3x from both sides.

$$0.1y=3-0.3x$$

The equation is in standard form.

$$0.1y=-\frac{3x}{10}+3$$

Multiply both sides by 10.

$$\frac{0.1y}{0.1}=\frac{-\frac{3x}{10}+3}{0.1}$$

Dividing by 0.1 undoes the multiplication by 0.1.

$$y=\frac{-\frac{3x}{10}+3}{0.1}$$

Divide 3-\frac{3x}{10} by 0.1 by multiplying 3-\frac{3x}{10} by the reciprocal of 0.1.

$$y=30-3x$$