Solve 0.20.12^2+0.2left(2*0.12right)^2+0.2left(3*0.12right)^2

$$0.2 { 0.12 }^{ 2 } +0.2 { \left(2 \cdot 0.12 \right) }^{ 2 } +0.2 { \left(3 \cdot 0.12 \right) }^{ 2 }$$

Evaluate

$$0.04032$$

Solution Steps

Calculate 0.12 to the power of 2 and get 0.0144.

$$0.2\times 0.0144+0.2\times \left(2\times 0.12\right)^{2}+0.2\times \left(3\times 0.12\right)^{2}$$

Multiply 0.2 and 0.0144 to get 0.00288.

$$0.00288+0.2\times \left(2\times 0.12\right)^{2}+0.2\times \left(3\times 0.12\right)^{2}$$

Multiply 2 and 0.12 to get 0.24.

$$0.00288+0.2\times 0.24^{2}+0.2\times \left(3\times 0.12\right)^{2}$$

Calculate 0.24 to the power of 2 and get 0.0576.

$$0.00288+0.2\times 0.0576+0.2\times \left(3\times 0.12\right)^{2}$$

Multiply 0.2 and 0.0576 to get 0.01152.

$$0.00288+0.01152+0.2\times \left(3\times 0.12\right)^{2}$$

Add 0.00288 and 0.01152 to get 0.0144.

$$0.0144+0.2\times \left(3\times 0.12\right)^{2}$$

Multiply 3 and 0.12 to get 0.36.

$$0.0144+0.2\times 0.36^{2}$$

Calculate 0.36 to the power of 2 and get 0.1296.

$$0.0144+0.2\times 0.1296$$

Multiply 0.2 and 0.1296 to get 0.02592.

$$0.0144+0.02592$$

Add 0.0144 and 0.02592 to get 0.04032.

$$0.04032$$

Factor

$$\frac{2 \cdot 7 \cdot 3 ^ {2}}{5 ^ {5}} = 0.04032$$