Solve 0.15sqrt{3600}-0.18sqrt{400}+{left(10sqrt{0.08}right)}^2

$$0.15 \sqrt{ 3600 } -0.18 \sqrt{ 400 } + { \left(10 \sqrt{ 0.08 } \right) }^{ 2 }$$

Evaluate

$$13.4$$

Solution Steps

Calculate the square root of 3600 and get 60.

$$0.15\times 60-0.18\sqrt{400}+\left(10\sqrt{0.08}\right)^{2}$$

Multiply 0.15 and 60 to get 9.

$$9-0.18\sqrt{400}+\left(10\sqrt{0.08}\right)^{2}$$

Calculate the square root of 400 and get 20.

$$9-0.18\times 20+\left(10\sqrt{0.08}\right)^{2}$$

Multiply -0.18 and 20 to get -3.6.

$$9-3.6+\left(10\sqrt{0.08}\right)^{2}$$

Subtract 3.6 from 9 to get 5.4.

$$5.4+\left(10\sqrt{0.08}\right)^{2}$$

Expand \left(10\sqrt{0.08}\right)^{2}.

$$5.4+10^{2}\left(\sqrt{0.08}\right)^{2}$$

Calculate 10 to the power of 2 and get 100.

$$5.4+100\left(\sqrt{0.08}\right)^{2}$$

The square of \sqrt{0.08} is 0.08.

$$5.4+100\times 0.08$$

Multiply 100 and 0.08 to get 8.

$$5.4+8$$

Add 5.4 and 8 to get 13.4.

$$13.4$$

Factor

$$\frac{67}{5} = 13\frac{2}{5} = 13.4$$