Solve 0.14=0.15*(1-.3*x)

$$0.14 = 0.15 \times (1-.3 \times x)$$

Solve for x

$$x=\frac{2}{9}\approx 0.222222222$$

Steps for Solving Linear Equation

Divide both sides by 0.15.

$$\frac{0.14}{0.15}=1-0.3x$$

Expand \frac{0.14}{0.15} by multiplying both numerator and the denominator by 100.

$$\frac{14}{15}=1-0.3x$$

Swap sides so that all variable terms are on the left hand side.

$$1-0.3x=\frac{14}{15}$$

Subtract 1 from both sides.

$$-0.3x=\frac{14}{15}-1$$

Convert 1 to fraction \frac{15}{15}.

$$-0.3x=\frac{14}{15}-\frac{15}{15}$$

Since \frac{14}{15} and \frac{15}{15} have the same denominator, subtract them by subtracting their numerators.

$$-0.3x=\frac{14-15}{15}$$

Subtract 15 from 14 to get -1.

$$-0.3x=-\frac{1}{15}$$

Divide both sides by -0.3.

$$x=\frac{-\frac{1}{15}}{-0.3}$$

Express \frac{-\frac{1}{15}}{-0.3} as a single fraction.

$$x=\frac{-1}{15\left(-0.3\right)}$$

Multiply 15 and -0.3 to get -4.5.

$$x=\frac{-1}{-4.5}$$

Expand \frac{-1}{-4.5} by multiplying both numerator and the denominator by 10.

$$x=\frac{-10}{-45}$$

Reduce the fraction \frac{-10}{-45} to lowest terms by extracting and canceling out -5.

$$x=\frac{2}{9}$$