Solve 0.12*1*10^-2=x(2*10^-2-1*10^-2)

$$0.12 \times 1 \times { 10 }^{ -2 } =x(2 \times { 10 }^{ -2 } -1 \times { 10 }^{ -2 } )$$

Solve for x

$$x=0.12$$

Steps for Solving Linear Equation

Multiply 0.12 and 1 to get 0.12.

$$0.12\times 10^{-2}=x\left(2\times 10^{-2}-1\times 10^{-2}\right)$$

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$0.12\times \frac{1}{100}=x\left(2\times 10^{-2}-1\times 10^{-2}\right)$$

Multiply 0.12 and \frac{1}{100} to get \frac{3}{2500}.

$$\frac{3}{2500}=x\left(2\times 10^{-2}-1\times 10^{-2}\right)$$

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$\frac{3}{2500}=x\left(2\times \frac{1}{100}-1\times 10^{-2}\right)$$

Multiply 2 and \frac{1}{100} to get \frac{1}{50}.

$$\frac{3}{2500}=x\left(\frac{1}{50}-1\times 10^{-2}\right)$$

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$\frac{3}{2500}=x\left(\frac{1}{50}-1\times \frac{1}{100}\right)$$

Multiply 1 and \frac{1}{100} to get \frac{1}{100}.

$$\frac{3}{2500}=x\left(\frac{1}{50}-\frac{1}{100}\right)$$

Subtract \frac{1}{100} from \frac{1}{50} to get \frac{1}{100}.

$$\frac{3}{2500}=x\times \frac{1}{100}$$

Swap sides so that all variable terms are on the left hand side.

$$x\times \frac{1}{100}=\frac{3}{2500}$$

Multiply both sides by 100, the reciprocal of \frac{1}{100}.

$$x=\frac{3}{2500}\times 100$$

Multiply \frac{3}{2500} and 100 to get \frac{3}{25}.

$$x=\frac{3}{25}$$