Solve 0.08*(100div43.2)*left(18div20right)^2

$$0.08 \times (100 \div 43.2) \times { \left(18 \div 20 \right) }^{ 2 }$$

Evaluate

$$0.15$$

Solution Steps

Expand \frac{100}{43.2} by multiplying both numerator and the denominator by 10.

$$0.08\times \frac{1000}{432}\times \left(\frac{18}{20}\right)^{2}$$

Reduce the fraction \frac{1000}{432} to lowest terms by extracting and canceling out 8.

$$0.08\times \frac{125}{54}\times \left(\frac{18}{20}\right)^{2}$$

Multiply 0.08 and \frac{125}{54} to get \frac{5}{27}.

$$\frac{5}{27}\times \left(\frac{18}{20}\right)^{2}$$

Reduce the fraction \frac{18}{20} to lowest terms by extracting and canceling out 2.

$$\frac{5}{27}\times \left(\frac{9}{10}\right)^{2}$$

Calculate \frac{9}{10} to the power of 2 and get \frac{81}{100}.

$$\frac{5}{27}\times \frac{81}{100}$$

Multiply \frac{5}{27} and \frac{81}{100} to get \frac{3}{20}.

$$\frac{3}{20}$$

Factor

$$\frac{3}{5 \cdot 2 ^ {2}} = 0.15$$