Solve 0.01(x-y)^2-9

$$0.01 ( x - y ) ^ { 2 } - 9$$

Evaluate

$$\frac{\left(x-y\right)^{2}}{100}-9$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-y\right)^{2}.

$$0.01\left(x^{2}-2xy+y^{2}\right)-9$$

Use the distributive property to multiply 0.01 by x^{2}-2xy+y^{2}.

$$0.01x^{2}-0.02xy+0.01y^{2}-9$$

Expand

$$-\frac{xy}{50}+\frac{x^{2}}{100}+\frac{y^{2}}{100}-9$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-y\right)^{2}.

$$0.01\left(x^{2}-2xy+y^{2}\right)-9$$

Use the distributive property to multiply 0.01 by x^{2}-2xy+y^{2}.

$$0.01x^{2}-0.02xy+0.01y^{2}-9$$