Solve 0.01+0.01^3/18*0.007^2

$$0.01 + \frac { 0.01 ^ { 3 } } { 18 \times 0.007 ^ { 2 } }$$

Evaluate

$$\frac{491}{44100}\approx 0.011133787$$

Solution Steps

Calculate 0.01 to the power of 3 and get 0.000001.

$$0.01+\frac{0.000001}{18\times 0.007^{2}}$$

Calculate 0.007 to the power of 2 and get 0.000049.

$$0.01+\frac{0.000001}{18\times 0.000049}$$

Multiply 18 and 0.000049 to get 0.000882.

$$0.01+\frac{0.000001}{0.000882}$$

Expand \frac{0.000001}{0.000882} by multiplying both numerator and the denominator by 1000000.

$$0.01+\frac{1}{882}$$

Convert decimal number 0.01 to fraction \frac{1}{100}.

$$\frac{1}{100}+\frac{1}{882}$$

Least common multiple of 100 and 882 is 44100. Convert \frac{1}{100} and \frac{1}{882} to fractions with denominator 44100.

$$\frac{441}{44100}+\frac{50}{44100}$$

Since \frac{441}{44100} and \frac{50}{44100} have the same denominator, add them by adding their numerators.

$$\frac{441+50}{44100}$$

Add 441 and 50 to get 491.

$$\frac{491}{44100}$$

Factor

$$\frac{491}{2 ^ {2} \cdot 3 ^ {2} \cdot 5 ^ {2} \cdot 7 ^ {2}} = 0.011133786848072562$$