Solve 0.0058*0.347*(1-x)=left(2*0.347right)^2div10

$$0.0058 \times 0.347 \times (1-x)= { \left(2 \times 0.347 \right) }^{ 2 } \div 10$$

Solve for x

$$x = -\frac{665}{29} = -22\frac{27}{29} \approx -22.931034483$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 10.

$$0.058\times 0.347\left(1-x\right)=\left(2\times 0.347\right)^{2}$$

Multiply 0.058 and 0.347 to get 0.020126.

$$0.020126\left(1-x\right)=\left(2\times 0.347\right)^{2}$$

Use the distributive property to multiply 0.020126 by 1-x.

$$0.020126-0.020126x=\left(2\times 0.347\right)^{2}$$

Multiply 2 and 0.347 to get 0.694.

$$0.020126-0.020126x=0.694^{2}$$

Calculate 0.694 to the power of 2 and get 0.481636.

$$0.020126-0.020126x=0.481636$$

Subtract 0.020126 from both sides.

$$-0.020126x=0.481636-0.020126$$

Subtract 0.020126 from 0.481636 to get 0.46151.

$$-0.020126x=0.46151$$

Divide both sides by -0.020126.

$$x=\frac{0.46151}{-0.020126}$$

Expand \frac{0.46151}{-0.020126} by multiplying both numerator and the denominator by 1000000.

$$x=\frac{461510}{-20126}$$

Reduce the fraction \frac{461510}{-20126} to lowest terms by extracting and canceling out 694.

$$x=-\frac{665}{29}$$