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0.0005x^{2}+0.0539x-1.5816=1.082
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
0.0005x^{2}+0.0539x-1.5816-1.082=1.082-1.082
Subtract 1.082 from both sides of the equation.
0.0005x^{2}+0.0539x-1.5816-1.082=0
Subtracting 1.082 from itself leaves 0.
0.0005x^{2}+0.0539x-2.6636=0
Subtract 1.082 from -1.5816 by finding a common denominator and subtracting the numerators. Then reduce the fraction to lowest terms if possible.
x=\frac{-0.0539±\sqrt{0.0539^{2}-4\times 0.0005\left(-2.6636\right)}}{2\times 0.0005}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 0.0005 for a, 0.0539 for b, and -2.6636 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-0.0539±\sqrt{0.00290521-4\times 0.0005\left(-2.6636\right)}}{2\times 0.0005}
Square 0.0539 by squaring both the numerator and the denominator of the fraction.
x=\frac{-0.0539±\sqrt{0.00290521-0.002\left(-2.6636\right)}}{2\times 0.0005}
Multiply -4 times 0.0005.
x=\frac{-0.0539±\sqrt{0.00290521+0.0053272}}{2\times 0.0005}
Multiply -0.002 times -2.6636 by multiplying numerator times numerator and denominator times denominator. Then reduce the fraction to lowest terms if possible.
x=\frac{-0.0539±\sqrt{0.00823241}}{2\times 0.0005}
Add 0.00290521 to 0.0053272 by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
x=\frac{-0.0539±\frac{\sqrt{823241}}{10000}}{2\times 0.0005}
Take the square root of 0.00823241.
x=\frac{-0.0539±\frac{\sqrt{823241}}{10000}}{0.001}
Multiply 2 times 0.0005.
x=\frac{\sqrt{823241}-539}{0.001\times 10000}
Now solve the equation x=\frac{-0.0539±\frac{\sqrt{823241}}{10000}}{0.001} when ± is plus. Add -0.0539 to \frac{\sqrt{823241}}{10000}.
x=\frac{\sqrt{823241}-539}{10}
Divide \frac{-539+\sqrt{823241}}{10000} by 0.001 by multiplying \frac{-539+\sqrt{823241}}{10000} by the reciprocal of 0.001.
x=\frac{-\sqrt{823241}-539}{0.001\times 10000}
Now solve the equation x=\frac{-0.0539±\frac{\sqrt{823241}}{10000}}{0.001} when ± is minus. Subtract \frac{\sqrt{823241}}{10000} from -0.0539.
x=\frac{-\sqrt{823241}-539}{10}
Divide \frac{-539-\sqrt{823241}}{10000} by 0.001 by multiplying \frac{-539-\sqrt{823241}}{10000} by the reciprocal of 0.001.
x=\frac{\sqrt{823241}-539}{10} x=\frac{-\sqrt{823241}-539}{10}
The equation is now solved.
0.0005x^{2}+0.0539x-1.5816=1.082
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
0.0005x^{2}+0.0539x-1.5816-\left(-1.5816\right)=1.082-\left(-1.5816\right)
Add 1.5816 to both sides of the equation.
0.0005x^{2}+0.0539x=1.082-\left(-1.5816\right)
Subtracting -1.5816 from itself leaves 0.
0.0005x^{2}+0.0539x=2.6636
Subtract -1.5816 from 1.082 by finding a common denominator and subtracting the numerators. Then reduce the fraction to lowest terms if possible.
\frac{0.0005x^{2}+0.0539x}{0.0005}=\frac{2.6636}{0.0005}
Multiply both sides by 2000.
x^{2}+\frac{0.0539}{0.0005}x=\frac{2.6636}{0.0005}
Dividing by 0.0005 undoes the multiplication by 0.0005.
x^{2}+107.8x=\frac{2.6636}{0.0005}
Divide 0.0539 by 0.0005 by multiplying 0.0539 by the reciprocal of 0.0005.
x^{2}+107.8x=5327.2
Divide 2.6636 by 0.0005 by multiplying 2.6636 by the reciprocal of 0.0005.
x^{2}+107.8x+53.9^{2}=5327.2+53.9^{2}
Divide 107.8, the coefficient of the x term, by 2 to get 53.9. Then add the square of 53.9 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+107.8x+2905.21=5327.2+2905.21
Square 53.9 by squaring both the numerator and the denominator of the fraction.
x^{2}+107.8x+2905.21=8232.41
Add 5327.2 to 2905.21 by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x+53.9\right)^{2}=8232.41
Factor x^{2}+107.8x+2905.21. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+53.9\right)^{2}}=\sqrt{8232.41}
Take the square root of both sides of the equation.
x+53.9=\frac{\sqrt{823241}}{10} x+53.9=-\frac{\sqrt{823241}}{10}
Simplify.
x=\frac{\sqrt{823241}-539}{10} x=\frac{-\sqrt{823241}-539}{10}
Subtract 53.9 from both sides of the equation.