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3x^{2}-12x=0
Swap sides so that all variable terms are on the left hand side.
x\left(3x-12\right)=0
Factor out x.
x=0 x=4
To find equation solutions, solve x=0 and 3x-12=0.
3x^{2}-12x=0
Swap sides so that all variable terms are on the left hand side.
x=\frac{-\left(-12\right)±\sqrt{\left(-12\right)^{2}}}{2\times 3}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, -12 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-12\right)±12}{2\times 3}
Take the square root of \left(-12\right)^{2}.
x=\frac{12±12}{2\times 3}
The opposite of -12 is 12.
x=\frac{12±12}{6}
Multiply 2 times 3.
x=\frac{24}{6}
Now solve the equation x=\frac{12±12}{6} when ± is plus. Add 12 to 12.
x=4
Divide 24 by 6.
x=\frac{0}{6}
Now solve the equation x=\frac{12±12}{6} when ± is minus. Subtract 12 from 12.
x=0
Divide 0 by 6.
x=4 x=0
The equation is now solved.
3x^{2}-12x=0
Swap sides so that all variable terms are on the left hand side.
\frac{3x^{2}-12x}{3}=\frac{0}{3}
Divide both sides by 3.
x^{2}+\left(-\frac{12}{3}\right)x=\frac{0}{3}
Dividing by 3 undoes the multiplication by 3.
x^{2}-4x=\frac{0}{3}
Divide -12 by 3.
x^{2}-4x=0
Divide 0 by 3.
x^{2}-4x+\left(-2\right)^{2}=\left(-2\right)^{2}
Divide -4, the coefficient of the x term, by 2 to get -2. Then add the square of -2 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-4x+4=4
Square -2.
\left(x-2\right)^{2}=4
Factor x^{2}-4x+4. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-2\right)^{2}}=\sqrt{4}
Take the square root of both sides of the equation.
x-2=2 x-2=-2
Simplify.
x=4 x=0
Add 2 to both sides of the equation.