Solve 0=-frac{sqrt{3}}{3}x+4

$$0=- \frac{ \sqrt{ 3 } }{ 3 } x+4$$

Solve for x

$$x=4\sqrt{3}\approx 6.92820323$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 3.

$$0=3\left(-\frac{\sqrt{3}}{3}\right)x+12$$

Express 3\left(-\frac{\sqrt{3}}{3}\right) as a single fraction.

$$0=\frac{-3\sqrt{3}}{3}x+12$$

Cancel out 3 and 3.

$$0=-\sqrt{3}x+12$$

Swap sides so that all variable terms are on the left hand side.

$$-\sqrt{3}x+12=0$$

Subtract 12 from both sides. Anything subtracted from zero gives its negation.

$$-\sqrt{3}x=-12$$

The equation is in standard form.

$$\left(-\sqrt{3}\right)x=-12$$

Divide both sides by -\sqrt{3}.

$$\frac{\left(-\sqrt{3}\right)x}{-\sqrt{3}}=-\frac{12}{-\sqrt{3}}$$

Dividing by -\sqrt{3} undoes the multiplication by -\sqrt{3}.

$$x=-\frac{12}{-\sqrt{3}}$$

Divide -12 by -\sqrt{3}.

$$x=4\sqrt{3}$$