Solve 0=x^2+16x+64

$$0= { x }^{ 2 } +16x+64$$

Solve for x

$$x=-8$$

Steps Using Factoring

Swap sides so that all variable terms are on the left hand side.

$$x^{2}+16x+64=0$$

To solve the equation, factor x^{2}+16x+64 using formula x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). To find a and b, set up a system to be solved.

$$a+b=16 ab=64$$

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 64.

$$1,64 2,32 4,16 8,8$$

Calculate the sum for each pair.

$$1+64=65 2+32=34 4+16=20 8+8=16$$

The solution is the pair that gives sum 16.

$$a=8 b=8$$

Rewrite factored expression \left(x+a\right)\left(x+b\right) using the obtained values.

$$\left(x+8\right)\left(x+8\right)$$

Rewrite as a binomial square.

$$\left(x+8\right)^{2}$$

To find equation solution, solve x+8=0.

$$x=-8$$

Steps Using Factoring By Grouping

Swap sides so that all variable terms are on the left hand side.

$$x^{2}+16x+64=0$$

To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as x^{2}+ax+bx+64. To find a and b, set up a system to be solved.

$$a+b=16 ab=1\times 64=64$$

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 64.

$$1,64 2,32 4,16 8,8$$

Calculate the sum for each pair.

$$1+64=65 2+32=34 4+16=20 8+8=16$$

The solution is the pair that gives sum 16.

$$a=8 b=8$$

Rewrite x^{2}+16x+64 as \left(x^{2}+8x\right)+\left(8x+64\right).

$$\left(x^{2}+8x\right)+\left(8x+64\right)$$

Factor out x in the first and 8 in the second group.

$$x\left(x+8\right)+8\left(x+8\right)$$

Factor out common term x+8 by using distributive property.

$$\left(x+8\right)\left(x+8\right)$$

Rewrite as a binomial square.

$$\left(x+8\right)^{2}$$

To find equation solution, solve x+8=0.

$$x=-8$$

Steps Using the Quadratic Formula

Swap sides so that all variable terms are on the left hand side.

$$x^{2}+16x+64=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 16 for b, and 64 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-16±\sqrt{16^{2}-4\times 64}}{2}$$

Square 16.

$$x=\frac{-16±\sqrt{256-4\times 64}}{2}$$

Multiply -4 times 64.

$$x=\frac{-16±\sqrt{256-256}}{2}$$

Add 256 to -256.

$$x=\frac{-16±\sqrt{0}}{2}$$

Take the square root of 0.

$$x=-\frac{16}{2}$$

Divide -16 by 2.

$$x=-8$$

Steps for Completing the Square

Swap sides so that all variable terms are on the left hand side.

$$x^{2}+16x+64=0$$

Factor x^{2}+16x+64. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x+8\right)^{2}=0$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x+8\right)^{2}}=\sqrt{0}$$

Simplify.

$$x+8=0 x+8=0$$

Subtract 8 from both sides of the equation.

$$x=-8 x=-8$$

The equation is now solved. Solutions are the same.

$$x=-8$$