Solve 0,9*(4/5*(-0,2)-21/25)

$$0,9 \cdot ( \frac { 4 } { 5 } \cdot ( - 0,2 ) - \frac { 21 } { 25 } )$$

Evaluate

$$-0,9$$

Solution Steps

Convert decimal number -0,2 to fraction -\frac{2}{10}. Reduce the fraction -\frac{2}{10} to lowest terms by extracting and canceling out 2.

$$0,9\left(\frac{4}{5}\left(-\frac{1}{5}\right)-\frac{21}{25}\right)$$

Multiply \frac{4}{5} times -\frac{1}{5} by multiplying numerator times numerator and denominator times denominator.

$$0,9\left(\frac{4\left(-1\right)}{5\times 5}-\frac{21}{25}\right)$$

Do the multiplications in the fraction \frac{4\left(-1\right)}{5\times 5}.

$$0,9\left(\frac{-4}{25}-\frac{21}{25}\right)$$

Fraction \frac{-4}{25} can be rewritten as -\frac{4}{25} by extracting the negative sign.

$$0,9\left(-\frac{4}{25}-\frac{21}{25}\right)$$

Since -\frac{4}{25} and \frac{21}{25} have the same denominator, subtract them by subtracting their numerators.

$$0,9\times \frac{-4-21}{25}$$

Subtract 21 from -4 to get -25.

$$0,9\times \frac{-25}{25}$$

Divide -25 by 25 to get -1.

$$0,9\left(-1\right)$$

Multiply 0,9 and -1 to get -0,9.

$$-0,9$$

Factor

$$-0,9$$