Solve 0,6m^2-mn-(m^2-3m+1)-(1/3m^2+m-5)

$$0,6 m ^ { 2 } - m n - ( m ^ { 2 } - 3 m + 1 ) - ( \frac { 1 } { 3 } m ^ { 2 } + m - 5 )$$

Evaluate

$$-mn-\frac{11m^{2}}{15}+2m+4$$

Solution Steps

To find the opposite of m^{2}-3m+1, find the opposite of each term.

$$0,6m^{2}-mn-m^{2}+3m-1-\left(\frac{1}{3}m^{2}+m-5\right)$$

Combine 0,6m^{2} and -m^{2} to get -0,4m^{2}.

$$-0,4m^{2}-mn+3m-1-\left(\frac{1}{3}m^{2}+m-5\right)$$

To find the opposite of \frac{1}{3}m^{2}+m-5, find the opposite of each term.

$$-0,4m^{2}-mn+3m-1-\frac{1}{3}m^{2}-m+5$$

Combine -0,4m^{2} and -\frac{1}{3}m^{2} to get -\frac{11}{15}m^{2}.

$$-\frac{11}{15}m^{2}-mn+3m-1-m+5$$

Combine 3m and -m to get 2m.

$$-\frac{11}{15}m^{2}-mn+2m-1+5$$

Add -1 and 5 to get 4.

$$-\frac{11}{15}m^{2}-mn+2m+4$$

Expand

$$-mn-\frac{11m^{2}}{15}+2m+4$$

Solution Steps

To find the opposite of m^{2}-3m+1, find the opposite of each term.

$$0,6m^{2}-mn-m^{2}+3m-1-\left(\frac{1}{3}m^{2}+m-5\right)$$

Combine 0,6m^{2} and -m^{2} to get -0,4m^{2}.

$$-0,4m^{2}-mn+3m-1-\left(\frac{1}{3}m^{2}+m-5\right)$$

To find the opposite of \frac{1}{3}m^{2}+m-5, find the opposite of each term.

$$-0,4m^{2}-mn+3m-1-\frac{1}{3}m^{2}-m+5$$

Combine -0,4m^{2} and -\frac{1}{3}m^{2} to get -\frac{11}{15}m^{2}.

$$-\frac{11}{15}m^{2}-mn+3m-1-m+5$$

Combine 3m and -m to get 2m.

$$-\frac{11}{15}m^{2}-mn+2m-1+5$$

Add -1 and 5 to get 4.

$$-\frac{11}{15}m^{2}-mn+2m+4$$