Solve 0,5*sqrt{12}*sqrt{6}*sqrt{2}+0,2

$$0,5 \cdot \sqrt { 12 } \cdot \sqrt { 6 } \cdot \sqrt { 2 } + 0,2$$

Evaluate

$$6,2$$

Solution Steps

Factor 12=6\times 2. Rewrite the square root of the product \sqrt{6\times 2} as the product of square roots \sqrt{6}\sqrt{2}.

$$0,5\sqrt{6}\sqrt{2}\sqrt{6}\sqrt{2}+0,2$$

Multiply \sqrt{6} and \sqrt{6} to get 6.

$$0,5\times 6\sqrt{2}\sqrt{2}+0,2$$

Multiply \sqrt{2} and \sqrt{2} to get 2.

$$0,5\times 6\times 2+0,2$$

Multiply 0,5 and 6 to get 3.

$$3\times 2+0,2$$

Multiply 3 and 2 to get 6.

$$6+0,2$$

Add 6 and 0,2 to get 6,2.

$$6,2$$

Factor

$$\frac{31}{5} = 6\frac{1}{5} = 6.2$$