Solve 0,3^3+0,7^3-sqrt[3]{(2,3-0,7)*0,2^2-2^-1}

$$0,3 ^ { 3 } + 0,7 ^ { 3 } - \sqrt[ 3 ] { ( 2,3 - 0,7 ) \cdot 0,2 ^ { 2 } - 2 ^ { - 1 } }$$

Evaluate

$$\frac{2^{\frac{2}{3}}}{2}\approx 0.793700526$$

Solution Steps

Calculate 3 to the power of 3 and get 27.

$$0\times 27+0\times 7^{3}-\sqrt[3]{\left(2,3-0,7\right)\times 0\times 2^{2}-2^{-1}}$$

Multiply 0 and 27 to get 0.

$$0+0\times 7^{3}-\sqrt[3]{\left(2,3-0,7\right)\times 0\times 2^{2}-2^{-1}}$$

Calculate 7 to the power of 3 and get 343.

$$0+0\times 343-\sqrt[3]{\left(2,3-0,7\right)\times 0\times 2^{2}-2^{-1}}$$

Multiply 0 and 343 to get 0.

$$0+0-\sqrt[3]{\left(2,3-0,7\right)\times 0\times 2^{2}-2^{-1}}$$

Add 0 and 0 to get 0.

$$0-\sqrt[3]{\left(2,3-0,7\right)\times 0\times 2^{2}-2^{-1}}$$

Subtract 0,7 from 2,3 to get 1,6.

$$0-\sqrt[3]{1,6\times 0\times 2^{2}-2^{-1}}$$

Multiply 1,6 and 0 to get 0.

$$0-\sqrt[3]{0\times 2^{2}-2^{-1}}$$

Calculate 2 to the power of 2 and get 4.

$$0-\sqrt[3]{0\times 4-2^{-1}}$$

Multiply 0 and 4 to get 0.

$$0-\sqrt[3]{0-2^{-1}}$$

Calculate 2 to the power of -1 and get \frac{1}{2}.

$$0-\sqrt[3]{0-\frac{1}{2}}$$

Subtract \frac{1}{2} from 0 to get -\frac{1}{2}.

$$0-\sqrt[3]{-\frac{1}{2}}$$