Solve 0,21[1,55-1,55(1000/2500)+(1000/2500)^2]

$$0,21 [ 1,55 - 1,55 ( \frac { 1000 } { 2500 } ) + ( \frac { 1000 } { 2500 } ) ^ { 2 } ]$$

Evaluate

$$0,2289$$

Solution Steps

Reduce the fraction \frac{1000}{2500} to lowest terms by extracting and canceling out 500.

$$0,21\left(1,55-1,55\times \frac{2}{5}+\left(\frac{1000}{2500}\right)^{2}\right)$$

Multiply 1,55 and \frac{2}{5} to get \frac{31}{50}.

$$0,21\left(1,55-\frac{31}{50}+\left(\frac{1000}{2500}\right)^{2}\right)$$

Subtract \frac{31}{50} from 1,55 to get \frac{93}{100}.

$$0,21\left(\frac{93}{100}+\left(\frac{1000}{2500}\right)^{2}\right)$$

Reduce the fraction \frac{1000}{2500} to lowest terms by extracting and canceling out 500.

$$0,21\left(\frac{93}{100}+\left(\frac{2}{5}\right)^{2}\right)$$

Calculate \frac{2}{5} to the power of 2 and get \frac{4}{25}.

$$0,21\left(\frac{93}{100}+\frac{4}{25}\right)$$

Add \frac{93}{100} and \frac{4}{25} to get \frac{109}{100}.

$$0,21\times \frac{109}{100}$$

Multiply 0,21 and \frac{109}{100} to get \frac{2289}{10000}.

$$\frac{2289}{10000}$$

Factor

$$\frac{3 \cdot 7 \cdot 109}{2 ^ {4} \cdot 5 ^ {4}} = 0.2289$$