Solve 0,01(x-y)^2-9

$$0,01 ( x - y ) ^ { 2 } - 9$$

Evaluate

$$\frac{\left(x-y\right)^{2}}{100}-9$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-y\right)^{2}.

$$0,01\left(x^{2}-2xy+y^{2}\right)-9$$

Use the distributive property to multiply 0,01 by x^{2}-2xy+y^{2}.

$$0,01x^{2}-0,02xy+0,01y^{2}-9$$

Expand

$$-\frac{xy}{50}+\frac{x^{2}}{100}+\frac{y^{2}}{100}-9$$

Solution Steps

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-y\right)^{2}.

$$0,01\left(x^{2}-2xy+y^{2}\right)-9$$

Use the distributive property to multiply 0,01 by x^{2}-2xy+y^{2}.

$$0,01x^{2}-0,02xy+0,01y^{2}-9$$