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0-25x-15
Anything times zero gives zero.
-15-25x
Subtract 15 from 0 to get -15.
x ^ 2 -25x -15 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 25 rs = -15
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = \frac{25}{2} - u s = \frac{25}{2} + u
Two numbers r and s sum up to 25 exactly when the average of the two numbers is \frac{1}{2}*25 = \frac{25}{2}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(\frac{25}{2} - u) (\frac{25}{2} + u) = -15
To solve for unknown quantity u, substitute these in the product equation rs = -15
\frac{625}{4} - u^2 = -15
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -15-\frac{625}{4} = -\frac{685}{4}
Simplify the expression by subtracting \frac{625}{4} on both sides
u^2 = \frac{685}{4} u = \pm\sqrt{\frac{685}{4}} = \pm \frac{\sqrt{685}}{2}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =\frac{25}{2} - \frac{\sqrt{685}}{2} = -0.586 s = \frac{25}{2} + \frac{\sqrt{685}}{2} = 25.586
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.
5\left(0-5x-3\right)
Factor out 5.