Solve 0x^2-23x+6>0

$$0 x ^ { 2 } - 23 x + 6 > 0$$

Solve for x

$$x<\frac{6}{23}$$

Solution Steps

Anything times zero gives zero.

$$0-23x+6>0$$

Add 0 and 6 to get 6.

$$6-23x>0$$

Subtract 6 from both sides. Anything subtracted from zero gives its negation.

$$-23x>-6$$

Divide both sides by -23. Since -23 is negative, the inequality direction is changed.

$$x<\frac{-6}{-23}$$

Fraction \frac{-6}{-23} can be simplified to \frac{6}{23} by removing the negative sign from both the numerator and the denominator.

$$x<\frac{6}{23}$$