Solve 0x^2-18x+0-0

$$0 x ^ { 2 } - 18 x + 0 - 0$$

Evaluate

$$-18x$$

Solution Steps

Anything times zero gives zero.

$$0-18x+0-0$$

Add 0 and 0 to get 0.

$$-18x-0$$

Differentiate w.r.t. x

$$-18$$

Steps Using Definition of a Derivative

Anything times zero gives zero.

$$\frac{\mathrm{d}}{\mathrm{d}x}(0-18x+0-0)$$

Add 0 and 0 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-18x-0)$$

Multiply -1 and 0 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-18x+0)$$

Anything plus zero gives itself.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-18x)$$

The derivative of ax^{n} is nax^{n-1}.

$$-18x^{1-1}$$

Subtract 1 from 1.

$$-18x^{0}$$

For any term t except 0, t^{0}=1.

$$-18$$