Solve 0x+y

$$0 x + y$$

Evaluate

$$y$$

Solution Steps

Anything times zero gives zero.

$$0+y$$

Anything plus zero gives itself.

$$y$$

Differentiate w.r.t. y

$$1$$

Steps Using Definition of a Derivative

Anything times zero gives zero.

$$\frac{\mathrm{d}}{\mathrm{d}y}(0+y)$$

Anything plus zero gives itself.

$$\frac{\mathrm{d}}{\mathrm{d}y}(y)$$

The derivative of ax^{n} is nax^{n-1}.

$$y^{1-1}$$

Subtract 1 from 1.

$$y^{0}$$

For any term t except 0, t^{0}=1.

$$1$$