Solve 0-5^2-2+1/5^0-2*(-3)^2=

$$0 - 5 ^ { 2 } - \frac { 2 + 1 } { 5 ^ { 0 } } - 2 \cdot ( - 3 ) ^ { 2 } =$$

Evaluate

$$-46$$

Solution Steps

Calculate 5 to the power of 2 and get 25.

$$0-25-\frac{2+1}{5^{0}}-2\left(-3\right)^{2}$$

Subtract 25 from 0 to get -25.

$$-25-\frac{2+1}{5^{0}}-2\left(-3\right)^{2}$$

Add 2 and 1 to get 3.

$$-25-\frac{3}{5^{0}}-2\left(-3\right)^{2}$$

Calculate 5 to the power of 0 and get 1.

$$-25-\frac{3}{1}-2\left(-3\right)^{2}$$

Anything divided by one gives itself.

$$-25-3-2\left(-3\right)^{2}$$

Subtract 3 from -25 to get -28.

$$-28-2\left(-3\right)^{2}$$

Calculate -3 to the power of 2 and get 9.

$$-28-2\times 9$$

Multiply 2 and 9 to get 18.

$$-28-18$$

Subtract 18 from -28 to get -46.

$$-46$$

Factor

$$-46$$