Solve 0-2[7+18-(3-12)]-[(7*3)-(18-2)+1]=

$$0 - 2 [ 7 + 18 - ( 3 - 12 ) ] - [ ( 7 \times 3 ) - ( 18 - 2 ) + 1 ] =$$

Evaluate

$$-74$$

Solution Steps

Add 7 and 18 to get 25.

$$0-2\left(25-\left(3-12\right)\right)-\left(7\times 3-\left(18-2\right)+1\right)$$

Subtract 12 from 3 to get -9.

$$0-2\left(25-\left(-9\right)\right)-\left(7\times 3-\left(18-2\right)+1\right)$$

The opposite of -9 is 9.

$$0-2\left(25+9\right)-\left(7\times 3-\left(18-2\right)+1\right)$$

Add 25 and 9 to get 34.

$$0-2\times 34-\left(7\times 3-\left(18-2\right)+1\right)$$

Multiply 2 and 34 to get 68.

$$0-68-\left(7\times 3-\left(18-2\right)+1\right)$$

Subtract 68 from 0 to get -68.

$$-68-\left(7\times 3-\left(18-2\right)+1\right)$$

Multiply 7 and 3 to get 21.

$$-68-\left(21-\left(18-2\right)+1\right)$$

Subtract 2 from 18 to get 16.

$$-68-\left(21-16+1\right)$$

Subtract 16 from 21 to get 5.

$$-68-\left(5+1\right)$$

Add 5 and 1 to get 6.

$$-68-6$$

Subtract 6 from -68 to get -74.

$$-74$$

Factor

$$-74$$