Solve 0sqrt{48}+4sqrt{12})divsqrt{6}

$$0 \sqrt { 48 } + 4 \sqrt { 12 } ) \div \sqrt { 6 }$$

Evaluate

$$8\sqrt{3}\approx 13.856406461$$

Solution Steps

Factor 48=4^{2}\times 3. Rewrite the square root of the product \sqrt{4^{2}\times 3} as the product of square roots \sqrt{4^{2}}\sqrt{3}. Take the square root of 4^{2}.

$$0\times 4\sqrt{3}+4\sqrt{12}$$

Multiply 0 and 4 to get 0.

$$0\sqrt{3}+4\sqrt{12}$$

Anything times zero gives zero.

$$0+4\sqrt{12}$$

Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.

$$0+4\times 2\sqrt{3}$$

Multiply 4 and 2 to get 8.

$$0+8\sqrt{3}$$

Anything plus zero gives itself.

$$8\sqrt{3}$$