Solve 0div4-18*3+(-9-9div3)^2

$$0 \div 4 - 18 \times 3 + ( - 9 - 9 \div 3 ) ^ { 2 }$$

Evaluate

$$90$$

Solution Steps

Zero divided by any non-zero number gives zero.

$$0-18\times 3+\left(-9-\frac{9}{3}\right)^{2}$$

Multiply 18 and 3 to get 54.

$$0-54+\left(-9-\frac{9}{3}\right)^{2}$$

Subtract 54 from 0 to get -54.

$$-54+\left(-9-\frac{9}{3}\right)^{2}$$

Divide 9 by 3 to get 3.

$$-54+\left(-9-3\right)^{2}$$

Subtract 3 from -9 to get -12.

$$-54+\left(-12\right)^{2}$$

Calculate -12 to the power of 2 and get 144.

$$-54+144$$

Add -54 and 144 to get 90.

$$90$$

Factor

$$2\times 3^{2}\times 5$$