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x^{2}-6x+5=0
Swap sides so that all variable terms are on the left hand side.
a+b=-6 ab=5
To solve the equation, factor x^{2}-6x+5 using formula x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). To find a and b, set up a system to be solved.
a=-5 b=-1
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. The only such pair is the system solution.
\left(x-5\right)\left(x-1\right)
Rewrite factored expression \left(x+a\right)\left(x+b\right) using the obtained values.
x=5 x=1
To find equation solutions, solve x-5=0 and x-1=0.
x^{2}-6x+5=0
Swap sides so that all variable terms are on the left hand side.
a+b=-6 ab=1\times 5=5
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as x^{2}+ax+bx+5. To find a and b, set up a system to be solved.
a=-5 b=-1
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. The only such pair is the system solution.
\left(x^{2}-5x\right)+\left(-x+5\right)
Rewrite x^{2}-6x+5 as \left(x^{2}-5x\right)+\left(-x+5\right).
x\left(x-5\right)-\left(x-5\right)
Factor out x in the first and -1 in the second group.
\left(x-5\right)\left(x-1\right)
Factor out common term x-5 by using distributive property.
x=5 x=1
To find equation solutions, solve x-5=0 and x-1=0.
x^{2}-6x+5=0
Swap sides so that all variable terms are on the left hand side.
x=\frac{-\left(-6\right)±\sqrt{\left(-6\right)^{2}-4\times 5}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -6 for b, and 5 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-6\right)±\sqrt{36-4\times 5}}{2}
Square -6.
x=\frac{-\left(-6\right)±\sqrt{36-20}}{2}
Multiply -4 times 5.
x=\frac{-\left(-6\right)±\sqrt{16}}{2}
Add 36 to -20.
x=\frac{-\left(-6\right)±4}{2}
Take the square root of 16.
x=\frac{6±4}{2}
The opposite of -6 is 6.
x=\frac{10}{2}
Now solve the equation x=\frac{6±4}{2} when ± is plus. Add 6 to 4.
x=5
Divide 10 by 2.
x=\frac{2}{2}
Now solve the equation x=\frac{6±4}{2} when ± is minus. Subtract 4 from 6.
x=1
Divide 2 by 2.
x=5 x=1
The equation is now solved.
x^{2}-6x+5=0
Swap sides so that all variable terms are on the left hand side.
x^{2}-6x=-5
Subtract 5 from both sides. Anything subtracted from zero gives its negation.
x^{2}-6x+\left(-3\right)^{2}=-5+\left(-3\right)^{2}
Divide -6, the coefficient of the x term, by 2 to get -3. Then add the square of -3 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-6x+9=-5+9
Square -3.
x^{2}-6x+9=4
Add -5 to 9.
\left(x-3\right)^{2}=4
Factor x^{2}-6x+9. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-3\right)^{2}}=\sqrt{4}
Take the square root of both sides of the equation.
x-3=2 x-3=-2
Simplify.
x=5 x=1
Add 3 to both sides of the equation.