Solve 0=m3/4+b

$$0 = m \frac { 3 } { 4 } + b$$

Solve for b

$$b=-\frac{3m}{4}$$

Solution Steps

Swap sides so that all variable terms are on the left hand side.

$$m\times \frac{3}{4}+b=0$$

Subtract m\times \frac{3}{4} from both sides. Anything subtracted from zero gives its negation.

$$b=-m\times \frac{3}{4}$$

Multiply -1 and \frac{3}{4} to get -\frac{3}{4}.

$$b=-\frac{3}{4}m$$

Solve for m

$$m=-\frac{4b}{3}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$m\times \frac{3}{4}+b=0$$

Subtract b from both sides. Anything subtracted from zero gives its negation.

$$m\times \frac{3}{4}=-b$$

The equation is in standard form.

$$\frac{3}{4}m=-b$$

Divide both sides of the equation by \frac{3}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{4}m}{\frac{3}{4}}=-\frac{b}{\frac{3}{4}}$$

Dividing by \frac{3}{4} undoes the multiplication by \frac{3}{4}.

$$m=-\frac{b}{\frac{3}{4}}$$

Divide -b by \frac{3}{4} by multiplying -b by the reciprocal of \frac{3}{4}.

$$m=-\frac{4b}{3}$$