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m^{2}-6m-11=0
Swap sides so that all variable terms are on the left hand side.
m=\frac{-\left(-6\right)±\sqrt{\left(-6\right)^{2}-4\left(-11\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -6 for b, and -11 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
m=\frac{-\left(-6\right)±\sqrt{36-4\left(-11\right)}}{2}
Square -6.
m=\frac{-\left(-6\right)±\sqrt{36+44}}{2}
Multiply -4 times -11.
m=\frac{-\left(-6\right)±\sqrt{80}}{2}
Add 36 to 44.
m=\frac{-\left(-6\right)±4\sqrt{5}}{2}
Take the square root of 80.
m=\frac{6±4\sqrt{5}}{2}
The opposite of -6 is 6.
m=\frac{4\sqrt{5}+6}{2}
Now solve the equation m=\frac{6±4\sqrt{5}}{2} when ± is plus. Add 6 to 4\sqrt{5}.
m=2\sqrt{5}+3
Divide 6+4\sqrt{5} by 2.
m=\frac{6-4\sqrt{5}}{2}
Now solve the equation m=\frac{6±4\sqrt{5}}{2} when ± is minus. Subtract 4\sqrt{5} from 6.
m=3-2\sqrt{5}
Divide 6-4\sqrt{5} by 2.
m=2\sqrt{5}+3 m=3-2\sqrt{5}
The equation is now solved.
m^{2}-6m-11=0
Swap sides so that all variable terms are on the left hand side.
m^{2}-6m=11
Add 11 to both sides. Anything plus zero gives itself.
m^{2}-6m+\left(-3\right)^{2}=11+\left(-3\right)^{2}
Divide -6, the coefficient of the x term, by 2 to get -3. Then add the square of -3 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
m^{2}-6m+9=11+9
Square -3.
m^{2}-6m+9=20
Add 11 to 9.
\left(m-3\right)^{2}=20
Factor m^{2}-6m+9. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(m-3\right)^{2}}=\sqrt{20}
Take the square root of both sides of the equation.
m-3=2\sqrt{5} m-3=-2\sqrt{5}
Simplify.
m=2\sqrt{5}+3 m=3-2\sqrt{5}
Add 3 to both sides of the equation.