Solve 0=a*b+a-2+b-4

$$0 = a * b + a - 2 + b - 4$$

Solve for a

$$a=-\frac{b-6}{b+1}$$

$$b\neq -1$$

Steps for Solving Linear Equation

Subtract 4 from -2 to get -6.

$$0=ab+a-6+b$$

Swap sides so that all variable terms are on the left hand side.

$$ab+a-6+b=0$$

Add 6 to both sides. Anything plus zero gives itself.

$$ab+a+b=6$$

Subtract b from both sides.

$$ab+a=6-b$$

Combine all terms containing a.

$$\left(b+1\right)a=6-b$$

Divide both sides by b+1.

$$\frac{\left(b+1\right)a}{b+1}=\frac{6-b}{b+1}$$

Dividing by b+1 undoes the multiplication by b+1.

$$a=\frac{6-b}{b+1}$$

Solve for b

$$b=-\frac{a-6}{a+1}$$

$$a\neq -1$$

Steps for Solving Linear Equation

Subtract 4 from -2 to get -6.

$$0=ab+a-6+b$$

Swap sides so that all variable terms are on the left hand side.

$$ab+a-6+b=0$$

Subtract a from both sides. Anything subtracted from zero gives its negation.

$$ab-6+b=-a$$

Add 6 to both sides.

$$ab+b=-a+6$$

Combine all terms containing b.

$$\left(a+1\right)b=-a+6$$

The equation is in standard form.

$$\left(a+1\right)b=6-a$$

Divide both sides by a+1.

$$\frac{\left(a+1\right)b}{a+1}=\frac{6-a}{a+1}$$

Dividing by a+1 undoes the multiplication by a+1.

$$b=\frac{6-a}{a+1}$$