Solve 0=6*a*-1+2b*1

$$0 = 6 \cdot a \cdot - 1 + 2 b \cdot 1$$

Solve for a

$$a=\frac{b}{3}$$

Steps for Solving Linear Equation

Multiply 6 and -1 to get -6.

$$0=-6a+2b\times 1$$

Multiply 2 and 1 to get 2.

$$0=-6a+2b$$

Swap sides so that all variable terms are on the left hand side.

$$-6a+2b=0$$

Subtract 2b from both sides. Anything subtracted from zero gives its negation.

$$-6a=-2b$$

Divide both sides by -6.

$$\frac{-6a}{-6}=-\frac{2b}{-6}$$

Dividing by -6 undoes the multiplication by -6.

$$a=-\frac{2b}{-6}$$

Divide -2b by -6.

$$a=\frac{b}{3}$$

Solve for b

$$b=3a$$

Steps for Solving Linear Equation

Multiply 6 and -1 to get -6.

$$0=-6a+2b\times 1$$

Multiply 2 and 1 to get 2.

$$0=-6a+2b$$

Swap sides so that all variable terms are on the left hand side.

$$-6a+2b=0$$

Add 6a to both sides. Anything plus zero gives itself.

$$2b=6a$$

Divide both sides by 2.

$$\frac{2b}{2}=\frac{6a}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$b=\frac{6a}{2}$$

Divide 6a by 2.

$$b=3a$$