Solve 0=3a*-2^2+2*b*-2+c

$$0 = 3 a \cdot - 2 ^ { 2 } + 2 \cdot b \cdot - 2 + c$$

Solve for a

$$a=\frac{c-4b}{12}$$

Steps for Solving Linear Equation

Calculate 2 to the power of 2 and get 4.

$$0=3a\left(-4\right)+2b\left(-2\right)+c$$

Multiply 3 and -4 to get -12.

$$0=-12a+2b\left(-2\right)+c$$

Multiply 2 and -2 to get -4.

$$0=-12a-4b+c$$

Swap sides so that all variable terms are on the left hand side.

$$-12a-4b+c=0$$

Add 4b to both sides. Anything plus zero gives itself.

$$-12a+c=4b$$

Subtract c from both sides.

$$-12a=4b-c$$

Divide both sides by -12.

$$\frac{-12a}{-12}=\frac{4b-c}{-12}$$

Dividing by -12 undoes the multiplication by -12.

$$a=\frac{4b-c}{-12}$$

Divide 4b-c by -12.

$$a=\frac{c}{12}-\frac{b}{3}$$

Solve for b

$$b=\frac{c-12a}{4}$$

Steps for Solving Linear Equation

Calculate 2 to the power of 2 and get 4.

$$0=3a\left(-4\right)+2b\left(-2\right)+c$$

Multiply 3 and -4 to get -12.

$$0=-12a+2b\left(-2\right)+c$$

Multiply 2 and -2 to get -4.

$$0=-12a-4b+c$$

Swap sides so that all variable terms are on the left hand side.

$$-12a-4b+c=0$$

Add 12a to both sides. Anything plus zero gives itself.

$$-4b+c=12a$$

Subtract c from both sides.

$$-4b=12a-c$$

Divide both sides by -4.

$$\frac{-4b}{-4}=\frac{12a-c}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$b=\frac{12a-c}{-4}$$

Divide 12a-c by -4.

$$b=\frac{c}{4}-3a$$