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20-p^{2}=0
Swap sides so that all variable terms are on the left hand side.
-p^{2}=-20
Subtract 20 from both sides. Anything subtracted from zero gives its negation.
p^{2}=\frac{-20}{-1}
Divide both sides by -1.
p^{2}=20
Fraction \frac{-20}{-1} can be simplified to 20 by removing the negative sign from both the numerator and the denominator.
p=2\sqrt{5} p=-2\sqrt{5}
Take the square root of both sides of the equation.
20-p^{2}=0
Swap sides so that all variable terms are on the left hand side.
-p^{2}+20=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
p=\frac{0±\sqrt{0^{2}-4\left(-1\right)\times 20}}{2\left(-1\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, 0 for b, and 20 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
p=\frac{0±\sqrt{-4\left(-1\right)\times 20}}{2\left(-1\right)}
Square 0.
p=\frac{0±\sqrt{4\times 20}}{2\left(-1\right)}
Multiply -4 times -1.
p=\frac{0±\sqrt{80}}{2\left(-1\right)}
Multiply 4 times 20.
p=\frac{0±4\sqrt{5}}{2\left(-1\right)}
Take the square root of 80.
p=\frac{0±4\sqrt{5}}{-2}
Multiply 2 times -1.
p=-2\sqrt{5}
Now solve the equation p=\frac{0±4\sqrt{5}}{-2} when ± is plus.
p=2\sqrt{5}
Now solve the equation p=\frac{0±4\sqrt{5}}{-2} when ± is minus.
p=-2\sqrt{5} p=2\sqrt{5}
The equation is now solved.