Solve 0=2(3)^3+5(3)^2-28(3)-18+y

$$0 = 2 ( 3 ) ^ { 3 } + 5 ( 3 ) ^ { 2 } - 28 ( 3 ) - 18 + y$$

Solve for y

$$y=3$$

Steps for Solving Linear Equation

Calculate 3 to the power of 3 and get 27.

$$0=2\times 27+5\times 3^{2}-28\times 3-18+y$$

Multiply 2 and 27 to get 54.

$$0=54+5\times 3^{2}-28\times 3-18+y$$

Calculate 3 to the power of 2 and get 9.

$$0=54+5\times 9-28\times 3-18+y$$

Multiply 5 and 9 to get 45.

$$0=54+45-28\times 3-18+y$$

Add 54 and 45 to get 99.

$$0=99-28\times 3-18+y$$

Multiply 28 and 3 to get 84.

$$0=99-84-18+y$$

Subtract 84 from 99 to get 15.

$$0=15-18+y$$

Subtract 18 from 15 to get -3.

$$0=-3+y$$

Swap sides so that all variable terms are on the left hand side.

$$-3+y=0$$

Add 3 to both sides. Anything plus zero gives itself.

$$y=3$$