Solve 0=-5x^2+Bx+0.05

$$0 = - 5 x ^ { 2 } + B x + 0.05$$

Solve for B

$$B=5x-\frac{1}{20x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-5x^{2}+Bx+0.05=0$$

Add 5x^{2} to both sides. Anything plus zero gives itself.

$$Bx+0.05=5x^{2}$$

Subtract 0.05 from both sides.

$$Bx=5x^{2}-0.05$$

The equation is in standard form.

$$xB=5x^{2}-0.05$$

Divide both sides by x.

$$\frac{xB}{x}=\frac{5x^{2}-0.05}{x}$$

Dividing by x undoes the multiplication by x.

$$B=\frac{5x^{2}-0.05}{x}$$

Divide 5x^{2}-0.05 by x.

$$B=5x-\frac{1}{20x}$$

Solve for x

$$x=\frac{-\sqrt{B^{2}+1}+B}{10}$$

$$x=\frac{\sqrt{B^{2}+1}+B}{10}$$