Solve 0=-8/3x-5+b

$$0 = - \frac { 8 } { 3 } x - 5 + b$$

Solve for b

$$b=\frac{8x}{3}+5$$

Solution Steps

Swap sides so that all variable terms are on the left hand side.

$$-\frac{8}{3}x-5+b=0$$

Add \frac{8}{3}x to both sides. Anything plus zero gives itself.

$$-5+b=\frac{8}{3}x$$

Add 5 to both sides.

$$b=\frac{8}{3}x+5$$

Solve for x

$$x=\frac{3\left(b-5\right)}{8}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-\frac{8}{3}x-5+b=0$$

Add 5 to both sides. Anything plus zero gives itself.

$$-\frac{8}{3}x+b=5$$

Subtract b from both sides.

$$-\frac{8}{3}x=5-b$$

Divide both sides of the equation by -\frac{8}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{8}{3}x}{-\frac{8}{3}}=\frac{5-b}{-\frac{8}{3}}$$

Dividing by -\frac{8}{3} undoes the multiplication by -\frac{8}{3}.

$$x=\frac{5-b}{-\frac{8}{3}}$$

Divide 5-b by -\frac{8}{3} by multiplying 5-b by the reciprocal of -\frac{8}{3}.

$$x=\frac{3b-15}{8}$$