Solve 0=sqrt{(-6-4)^2}+1(-3-(-7))^2

$$0 = \sqrt { ( - 6 - 4 ) ^ { 2 } } + 1 ( - 3 - ( - 7 ) ) ^ { 2 }$$

Verify

Solution Steps

Subtract 4 from -6 to get -10.

$$0=\sqrt{\left(-10\right)^{2}}+1\left(-3-\left(-7\right)\right)^{2}$$

Calculate -10 to the power of 2 and get 100.

$$0=\sqrt{100}+1\left(-3-\left(-7\right)\right)^{2}$$

Calculate the square root of 100 and get 10.

$$0=10+1\left(-3-\left(-7\right)\right)^{2}$$

The opposite of -7 is 7.

$$0=10+1\left(-3+7\right)^{2}$$

Add -3 and 7 to get 4.

$$0=10+1\times 4^{2}$$

Calculate 4 to the power of 2 and get 16.

$$0=10+1\times 16$$

Multiply 1 and 16 to get 16.

$$0=10+16$$

Add 10 and 16 to get 26.

$$0=26$$

Compare 0 and 26.

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