Solve 0=1/2(-1)^2-(-1)+c

$$0 = \frac { 1 } { 2 } ( - 1 ) ^ { 2 } - ( - 1 ) + c$$

Solve for c

$$c = -\frac{3}{2} = -1\frac{1}{2} = -1.5$$

Steps for Solving Linear Equation

Calculate -1 to the power of 2 and get 1.

$$0=\frac{1}{2}\times 1-\left(-1\right)+c$$

Multiply \frac{1}{2} and 1 to get \frac{1}{2}.

$$0=\frac{1}{2}-\left(-1\right)+c$$

The opposite of -1 is 1.

$$0=\frac{1}{2}+1+c$$

Convert 1 to fraction \frac{2}{2}.

$$0=\frac{1}{2}+\frac{2}{2}+c$$

Since \frac{1}{2} and \frac{2}{2} have the same denominator, add them by adding their numerators.

$$0=\frac{1+2}{2}+c$$

Add 1 and 2 to get 3.

$$0=\frac{3}{2}+c$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{3}{2}+c=0$$

Subtract \frac{3}{2} from both sides. Anything subtracted from zero gives its negation.

$$c=-\frac{3}{2}$$