Solve for a
a=\frac{7y}{40}-2.5
Solve for y
y=\frac{40a+100}{7}
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y-0.4a=0.93y+1
Swap sides so that all variable terms are on the left hand side.
-0.4a=0.93y+1-y
Subtract y from both sides.
-0.4a=-0.07y+1
Combine 0.93y and -y to get -0.07y.
-0.4a=-\frac{7y}{100}+1
The equation is in standard form.
\frac{-0.4a}{-0.4}=\frac{-\frac{7y}{100}+1}{-0.4}
Divide both sides of the equation by -0.4, which is the same as multiplying both sides by the reciprocal of the fraction.
a=\frac{-\frac{7y}{100}+1}{-0.4}
Dividing by -0.4 undoes the multiplication by -0.4.
a=\frac{7y}{40}-\frac{5}{2}
Divide -\frac{7y}{100}+1 by -0.4 by multiplying -\frac{7y}{100}+1 by the reciprocal of -0.4.
0.93y+1-y=-0.4a
Subtract y from both sides.
-0.07y+1=-0.4a
Combine 0.93y and -y to get -0.07y.
-0.07y=-0.4a-1
Subtract 1 from both sides.
-0.07y=-\frac{2a}{5}-1
The equation is in standard form.
\frac{-0.07y}{-0.07}=\frac{-\frac{2a}{5}-1}{-0.07}
Divide both sides of the equation by -0.07, which is the same as multiplying both sides by the reciprocal of the fraction.
y=\frac{-\frac{2a}{5}-1}{-0.07}
Dividing by -0.07 undoes the multiplication by -0.07.
y=\frac{40a+100}{7}
Divide -\frac{2a}{5}-1 by -0.07 by multiplying -\frac{2a}{5}-1 by the reciprocal of -0.07.
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Limits
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