Solve .3x7+4x=12.5

$$.3 x 7 + 4 x = 12.5$$

Solve for x

$$x=-\frac{3x_{7}}{40}+3.125$$

Steps for Solving Linear Equation

Subtract 0.3x_{7} from both sides.

$$4x=12.5-0.3x_{7}$$

The equation is in standard form.

$$4x=-\frac{3x_{7}}{10}+12.5$$

Divide both sides by 4.

$$\frac{4x}{4}=\frac{-\frac{3x_{7}}{10}+12.5}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$x=\frac{-\frac{3x_{7}}{10}+12.5}{4}$$

Divide 12.5-\frac{3x_{7}}{10} by 4.

$$x=-\frac{3x_{7}}{40}+\frac{25}{8}$$

Solve for x_7

$$x_{7}=\frac{125-40x}{3}$$

Steps for Solving Linear Equation

Subtract 4x from both sides.

$$0.3x_{7}=12.5-4x$$

Divide both sides of the equation by 0.3, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{0.3x_{7}}{0.3}=\frac{12.5-4x}{0.3}$$

Dividing by 0.3 undoes the multiplication by 0.3.

$$x_{7}=\frac{12.5-4x}{0.3}$$

Divide 12.5-4x by 0.3 by multiplying 12.5-4x by the reciprocal of 0.3.

$$x_{7}=\frac{125-40x}{3}$$