Solve for x
x=-\frac{y}{3}+40
Solve for y
y=120-3x
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0.15x+0.05y=6
Multiply 0.6 and 10 to get 6.
0.15x=6-0.05y
Subtract 0.05y from both sides.
0.15x=-\frac{y}{20}+6
The equation is in standard form.
\frac{0.15x}{0.15}=\frac{-\frac{y}{20}+6}{0.15}
Divide both sides of the equation by 0.15, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{-\frac{y}{20}+6}{0.15}
Dividing by 0.15 undoes the multiplication by 0.15.
x=-\frac{y}{3}+40
Divide 6-\frac{y}{20} by 0.15 by multiplying 6-\frac{y}{20} by the reciprocal of 0.15.
0.15x+0.05y=6
Multiply 0.6 and 10 to get 6.
0.05y=6-0.15x
Subtract 0.15x from both sides.
0.05y=-\frac{3x}{20}+6
The equation is in standard form.
\frac{0.05y}{0.05}=\frac{-\frac{3x}{20}+6}{0.05}
Multiply both sides by 20.
y=\frac{-\frac{3x}{20}+6}{0.05}
Dividing by 0.05 undoes the multiplication by 0.05.
y=120-3x
Divide 6-\frac{3x}{20} by 0.05 by multiplying 6-\frac{3x}{20} by the reciprocal of 0.05.
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